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14th March 2016, 03:45 PM
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Join Date: May 2012
Re: MBA Maths By Amiya

the questions on the Mathematics Subject for practice which are provided by 3E learning Institute are as given below:

1. Mom demanded you to purchase 10 fruits of exactly 3 different types. Then how

many different ways you can full fill her demand from a fruit market where you

found 12 different types of fruits enough to full fill demand of a village.

a. Infinite b. 12c3 c. 12c3*12c2 d. 12c3*9c2 e. NoT

Sol: a+b+c = 10 => 9c2*12c3

2. In how many ways we can arrange 20 people on a regular decagon such that people

are sitting on the vertex and middle of the sides

a. 19! b. 19!/2 c.2*19! d. None of these

Ans : 2*19!

3. There are how many times digit 5 come, if we write number from 189 to 5004

(including both)

a. 1460 b. 1462 c.1466 d. None of these

0000 to 4999

5 at unit place - 5*10*10 = 500

5 at 10th place - 5*10*10 = 500

5 at 100th place - 5*10*10 = 500

5 from 0000 to 4999 =

500+500+500 = 1500

000 - 199

5 at unit place - 2*10 = 20

5 at 10th place - 2*10 = 20

189 - 199

5comes only 1 place

5000-5004 = 5

Total number of 5 = [0000 to 4999]

- [000-199] + [189-199] +5 = 1500

- 40 +1 +5

= 1466

4. Total number of integral ordered pair solution of a*b*c=1001^2

a. 27 b. 27c3 c. 216 d.864 e. NoT

Sol 864

a*b*c=1001^2 = 7^2*11^2*13^2

Required solution = (4C2)^3(3c0+3c1)

5. There are how many four digits numbers are in which all digits are prime and

when we add 5 in the number the resultant numbers also have all prime digits.

a. 64 b. 70 c. 76 d.80 e. NoT

Sol: 2,3,5,7

If last digit 2 , then total no = 4*4*4 = 64

If last digit is 7 and second last digit is 2 , = 4*4 = 16

Total =80

6. In how many different way one a put 12 different rings in his 5 fingers of one hand

such that each finger should have minimum 2 ring.

a. 12! b. 6P2*12! c. 6c4*12! d.12!/(4!)^3 e. NoT

Sol:[c]

a+b+c+d+e= 12

with minimum two condition, 6c2*12!

7. Total number of odd positive integral solution of a+b+c+d <12

a. 16c4 b. 2^5 c. 11c3 d.12c4 e. NoT

Sol: [b]

a+b+c+d <12

a+b+c+d <=11 => a+b+c+d+e

<=11

(2m+1)+ (2n+1)+ (2k+1)+

(2l+1)+(2j+1) <=11

(2m)+ (2n)+ (2k)+ (2l)+(2j) <=6

(m)+ (n)+ (k)+ (l)+(j) <=3

So total number of odd solutions = 7c4

8. Coefficient of x^2*y^3*z in (1-x-y-z)^20

a. 20!/[(14!)*(2!)*(2!)] b. 20!/[(14!)*(2!)*(3!)]

c. - 3*20!/[(14!)*(3!)^2] d. None of these

Sol: [b] distribution of powers 20!/[(14!)*(2!)*(3!)]

9.How many terms of ((13)^(0.5)*x - (3y)^(0.2)*y)^100 has integral coefficient

a. 20 b. 10 c. 11 d. 100 e. None of these

Sol: [c]

2a + 5b = 100 , total 11 non negative integral solution.

0. If w+ 5x + 5y + 5z = N has 165 non negative integral solution then what is the value of Max(N)

a. 50 b. 45 c. 49 d. 44 d. none of these

Sol: 5*9 -1 = 44


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