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COMPREHENSION 1 (For question No. 1-3)
A plane mirror is inclined at angle with x-axis. The point P is on the
mirror. An incident ray MP, after reflection at point P of the mirror,
passes through point A as shown in the figure. Read the passage
carefully and answer the following questions
1. The value of is
(A) 30 (B) 45
(C) 60 (D) 90
P 0, 4 3 cm
O
X
M
A 4cm, 0
Y
2. Now the mirror is rotated is such a way so that the incident ray MP, after reflection at point P of
the mirror, pass through the origin, then
(A) mirror must be rotated by angle 15 anticlockwise
(B) mirror must be rotated by angle 15 clockwise
(C) mirror must be rotated by angle 30 anticlockwise
(D) mirror must be rotated by angle 30 clockwise
3. Which of the following optical instruments works on the principle of reflection of light from plane
mirror?
(A) magnifying glass (B) Telescope
(C) Periscope (D) Microscope
Consider the reaction of acidified potassium permanganate with sodium sulphite as follows:
2 2 2 MnO H SO Mn SO H O 4 3 4 2
It is a redox reaction in which one species is getting oxidized by losing electron/s and other is getting
reduced by gaining electron/s.
The number of electrons which the atom of an element loses or gains in going from its free elemental
state (which is 0) to its new state in that particular compound is called the Oxidation Number (O.N.) of the
element in that compound.
The oxidation number of an element in a compound is determined by the algebraic sum of oxidation
numbers of the individual atoms, each multiplied by the number of atoms of the element in the molecule
which is = 0 (in case of a compound) and for an ion is equal to the charge present. For example the
algebraic sum of O.N. of atoms in H2O is shown as below :
(oxidation number of oxygen is generally 2, O.N. of hydrogen = +1)
H2O
(+1) 2 + (2) = 0
The substance which undergoes reduction is called an oxidant and that which undergoes oxidation is
called a reductant.
Answer the following questions:
4. Which species is getting reduced in the above reaction?
(A) MnO4
(B) H
(C) 2 SO3
(D) 2 Mn
5. Which species is acting as a reductant?
(A) MnO4
(B) H
+
(C) 2 SO3
(D) Mn2+
6. If equivalent weight = Molecular weight
Valence factor
where valence factor = no. of electrons lost or gained by one molecule of reductant or oxidant in a
reaction and is calculated by taking the difference of O. N. of that element in the reactant & the
product. It is always positive.
What will be the equivalent weight of KMnO4 in the above reaction?
(At. Mass K = 39; Mn = 55; O =16)
(A) 158 (B) 79
(C) 39.5 (D) 31.6
FIITJEE Talent Reward for Class 10th Question paper 
