#1
9th April 2015, 09:22 AM
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IIT Roorkee CGPA conversion formula
I am student of the IIT Roorkee? I am searching for the IIT Roorkee percentage to CGPA conversion formula? Can you please provide me IIT Roorkee percentage to CGPA conversion formula? Also provide me its CGPA calcaltor?
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#2
1st September 2018, 01:21 PM
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Re: IIT Roorkee CGPA conversion formula
Hii sir, I Wants to get the CGPA Conversion formula of the Indian Institute of Technology Roorkee ?
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#3
1st September 2018, 01:21 PM
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Re: IIT Roorkee CGPA conversion formula
Indian Institute of Technology Roorkee, formerly University of Roorkee and Thomason College of Civil Engineering, is a public engineering university located in Roorkee, Uttarakhand, India. Example: If a student have got total 9.6 CGPA, it means his/her total percentage of marks: 9.5*9.6 = 91.2%. To convert GPA into percentage you just need to multiply you grading point with 9.5 . For example if your score is 9.8 GPA , then in % it will be 9.8*9.5=93.1%. The B.tech Course Information of the Indian Institute of Technology Roorkee is given below B.tech In Bio Technology Chemical Engineering Civil Engineering Computer Science and Engineering Electrical Engineering Electronics and Communication Engineering Engineering Physics Mechanical Engineering Metallurgical and Materials Engineering Polymer Science and Engineering Production and Industrial Engineering Duration : 4 year Admission Criteria It is a two step process. One needs to qualify JEE (Main) exam and then take JEE (Advanced). One must have secured at least 75% marks (65% for SC/ST/PwD) in Class XII OR One must be within the category-wise top 20 percentile in his/her respective Class XII board examination. For more Information you may Contact to the Indian Institute of Technology Roorkee the contact Details Are given below Contact Information : Indian Institute of Technology Roorkee Address: Roorkee - Haridwar Highway, Roorkee, Uttarakhand 247667 |