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  #2  
1st September 2018, 01:21 PM
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Re: IIT Roorkee CGPA conversion formula

Hii sir, I Wants to get the CGPA Conversion formula of the Indian Institute of Technology Roorkee ?
  #3  
1st September 2018, 01:21 PM
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Join Date: Aug 2012
Re: IIT Roorkee CGPA conversion formula

Indian Institute of Technology Roorkee, formerly University of Roorkee and Thomason College of Civil Engineering, is a public engineering university located in Roorkee, Uttarakhand, India.


Example: If a student have got total 9.6 CGPA, it means his/her total percentage of marks: 9.5*9.6 = 91.2%. To convert GPA into percentage you just need to multiply you grading point with 9.5 . For example if your score is 9.8 GPA , then in % it will be 9.8*9.5=93.1%.

The B.tech Course Information of the Indian Institute of Technology Roorkee is given below


B.tech In

Bio Technology
Chemical Engineering
Civil Engineering
Computer Science and Engineering
Electrical Engineering
Electronics and Communication Engineering
Engineering Physics
Mechanical Engineering
Metallurgical and Materials Engineering
Polymer Science and Engineering
Production and Industrial Engineering

Duration : 4 year

Admission Criteria

It is a two step process. One needs to qualify JEE (Main) exam and then take JEE (Advanced).
One must have secured at least 75% marks (65% for SC/ST/PwD) in Class XII OR One must be within the category-wise top 20 percentile in his/her respective Class XII board examination.

For more Information you may Contact to the Indian Institute of Technology Roorkee the contact Details Are given below

Contact Information :

Indian Institute of Technology Roorkee
Address: Roorkee - Haridwar Highway, Roorkee, Uttarakhand 247667


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