#1
9th November 2017, 11:17 AM
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IIT JEE Shortcut Methods
Hii sir, I Am Preparing for the IIT JEE Examination I Wants to Know Some Shortcut Methods for Doing Calculation Faster for the Mathematic Section?
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#2
9th November 2017, 01:13 PM
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Re: IIT JEE Shortcut Methods
IIT JEE is Joint Entrance Exam that is Conducted for Admission Into the Undergraduate Engineer And Architecture Courses of the Colleges of India . The Examination is Conducted by CBSE . MULTIPLICATION OF 11 WITH ANY NUMBER OF 3 DIGITS. 1.352*11 = 3---(3+5)---(5+2)---2 = 3872 Means insert the sum of first and second digits, then sum of second and third digits between the two terminal digits of the number 213*11 = 2---(2+1)---(1+3)---3 = 2343 EXAMPLE. Here an extra case arises Consider the following examples for that 1) 329*11 = 3--- (3+2) +1--- (2+9-10) ---9 = 3619 Means, if sum of two digits of the number is greater than 10, then add 1 to previous digit and subtract 10 to the associated digit. 2)758*11 = 7+1---(7+5-10)+1---(5+8-10)---8 = 8338 TO CALCULATE REMINDER ON DIVIDING THE NUMBER BY 27 AND 37 consider number 34568276, we have to calculate the reminder on diving this number by 27 and 37 respectively. make triplets as written below starting from units place 34.........568..........276 now sum of all triplets = 34+568+276 = 878 divide it by 27 we get reminder as 14 divide it by 37 we get reminder as 27 EXAMPLE. other examples for the clarification of the rule let the number is 2387850765 triplets are 2...387...850...765 sum of the triplets = 2+387+850+765 = 2004 on revising the steps we get 2......004 sum = 6 divide it by 27 we get reminder as 6 divide it by 37 we get reminder as 6 Is this maths trick helpful? Yes (11394) No (4622) Post / Read comment (47) TO CALCULATE REMINDER ON DIVIDING THE NUMBER BY 7 11 AND 13 Let me explain this rule by taking examples consider number 34568276, we have to calculate the reminder on diving this number by 7 11 and 13 respectively. make triplets as written below starting from units place 34.........568..........276 now alternate sum = 34+276 = 310 and 568 and difference of these sums = 568-310 = 258 divide it by 7 we get reminder as 6 divide it by 11 we get reminder as 5 divide it by 13 we get reminder as 11 EXAMPLE. other examples:- consider the number 4523895099854 triplet pairs are 4...523...895...099...854 alternate sums are 4+895+854=1753 and 523+099=622 difference = 1131 revise the same tripling process 1......131 so difference = 131-1 = 130 divide it by 7 we get reminder as 4 divide it by 11 we get reminder as 9 divide it by 13 we get reminder as 0 |
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