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24th February 2016, 11:10 AM
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Join Date: May 2012
Re: IAS Exam Questions Maths

Hello, here I am providing you the questions of the maths paper of IAS exam as under:

If both x and y are prime numbers, which of the following CANNOT be the difference of x and y?
(A) 1
(B) 3
(C) 9
(D) 15
(E) 23

Answer:
Choice E is correct. This problem is solved fastest by process of elimination. Both 2 and 3 are prime and their difference is one (Eliminate Choice A). Both 5 and 2 are prime and their difference is 3 (Eliminate Choice B). Both 11 and 2 are prime and their difference is 9 (Eliminate C). Both 17 and 2 are prime and their difference is 15 (Eliminate D)

3+5+6=151872

5+5+6=253094

5+6+7=303585

5+5+3=251573

then 9+4+7=_______?

Answer
The solution to the first 4 digits is pretty straight forward, and I am sure most of you must have easily got it.

It works out to be a+b+c = (a*b)(a*c)??

The last 2 digits are really tough to crack…

Here’s how you do it. Reverse of {(a×b)+(a×c)-c}

So the number would (a×b),(a×c),{(a×b)+(a×c)-c}reverse.

So for 1st one: 3+5+6=151872;
axb = 3×5 = 15; axc = 3×6 = 18;
{(a×b)+(a×c)-c} = ((3×5)+(3×6)-6} = 27
— Reverse of 27 is 72

So 9+4+7=_______?

axb = 9×4 = 36;
axc = 9×7 = 63;
{(a×b)+(a×c)-c} = ((9×4)+(9×7)-7} = (36+63-7)=92
— Reverse of 92 is 29.
Hence 9+4+7 = 366329

Can you make 10 plus 4 = 2 ?
Solution
10 o'clock + 4 hours = 2 o'clock

The number log20 3 lies in
A. (3/4, 4/5) B. (1/3, 1/2) C. (1/2, 3/4) D. (1/4, 1/3)

For x1, x2, y1, y2 Î R, if 0 < x1 < x2, y1 = y2 and z1 = x1 + i y1, z2 = x2 + i y2 and z3 = 1/2(z1 + z2), then z1, z2, and z3 satisfy
A. | z1 | < | z3 | < | z2 | B. | z1 | > | z2 | > | z3 | C. | z1 | < | z2 | < | z3 | D. | z1 | = | z2 | = | z3 |


Which of the following is not true in linear programming problem?
A. A column in the simplex table that contains all of the variables in the solution is called pivot or key column.
B. A basic solution which is also in the feasible region is called a basic feasible solution.
C. A surplus variable is a variable subtracted from the left hand side of a greater than or equal to constraint to convert it into an equality.
D. A slack variable is a variable added to the left hand side of a less than or equal to constraint to convert it into an equality.

The equation of the circle whose diameter lies on 2x + 3y = 3 and 16x - y = 4 and which passes through (4, 6) is
A. x2 + y2 = 40 B. 5(x2 + y2) - 4x - 8y = 200
C. x2 + y2 - 4x - 8y = 200 D. 5(x2 + y2) - 3x - 8y = 200

Let n(A) = 4 and n(B) = 5. The number of all possible injections from A to B is
A. 120 B. 9 C. 24 D. none

Here I am providing you more maths paper fro practice as under:
Attached Files
File Type: pdf IAS maths paper.pdf (551.5 KB, 121 views)


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