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5th August 2014, 02:30 PM
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Join Date: Apr 2013
Re: Question Papers with Solutions of CAPGEMINI

Here I am giving you solved question paper for CAPGEMINI placement examination in a file attached with it so you can get it easily.

1. The average salary of 3 workers is 95 Rs. per week. If one earns Rs.115 and second earns Rs.65 how much is the salary of the 3rd worker.
Ans.105.

2. A 16 stored building has 12000 sq.feet on each floor. Company A rents 7 floors and company B rents 4 floors. What is the number of sq.feet of unrented floor space.
Ans.60000

3.During a given week A programmer spends 1/4 of his time preparing flow chart, 3/8 of his time coding and the rest of the time in debugging the programs. If he works 48 hours during the week , how many hours did he spend debugging the program.
Ans. 18.

4. A company installed 36 machines at the beginning of the year. In March they installed 9 additional machines and then disconnected 18 in August. How many were still installed at the end of the year.
Ans. 27

5. A man owns 2/3 of the market research beauro business and sells 3/4 of his shares for Rs. 75000. What is the value of Business ?
Ans.150000

6. If 12 file cabinets require 18 feet of wall space, how many feet of wall space will 30 cabinets require?
Ans.45

7. A computer printer produced 176,400 lines in a given day. If the printer was in operation for seven hours during the day, how many lines did it print per minute?
Ans.420

8. From its total income, A sales company spent Rs.20,000 for advertising, half of the remainder on commissions and had Rs.6000 left. What was its total income?
Ans.32000

9. On Monday a banker processed a batch of cheques, on Tuesday she processed three times as many, and on Wednesday she processed 4000 cheques. In the three days, she processed 16000 cheques. How many did she process on Tuesday?
Ans.9000

10. The cost of four dozen proof machine ribbons and five dozen accouting machine ribbons was Rs.160/-. If one dozen accounting machine ribbons cost Rs.20/-, what is the cost of a dozen proof machine ribbons?
Ans.Rs.15

11. If a clerk can process 80 cheques in half an hour, how many cheques can she process in a seven and one half hour day?
Ans.1200

12. In a library, there are two racks with 40 books per rack. On a given day, 30 books were issued. What fraction remained in the racks?
Ans.5/8

13. The average length of three tapes is 6800 feet. None of the tapes is less than 6400 feet. What is the greatest possible length of one of the other tapes?
Ans.7600

14. A company rented a machine for Rs.700/- a month. Five years later the treasurer calculated that if the company had purchased the machine and paid Rs.100/- monthly maintenance charge, the company would have saved
Rs.2000/-. What was the purchase price of the machine?
Ans.Rs.34000

CAPGEMINI solved paper


1. In water, the direction along the stream is called downstream. And, the direction against the stream is called upstream.

2. If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then:

Speed downstream = (u + v) km/hr.

Speed upstream = (u - v) km/hr.

3. If the speed in downstream is a km/hr and the speed in upstream is b km/hr, then:

Speed in still water = (a + b)/2 km/hr.

Rate of stream =(a - b)/2 km/hr

Question 1

A motorboat can cover 10 1/3 km in 1 hour in still water. And it takes twice as much as time to cover up than as to cover down the same distance in running water. The speed of the current is:

a)3 4/9 km/hr b) 2 1/3 km/hr c) 4 km/hr d) none of these

Answer : a) 3 4/9 km/hr

Solution :

Let the speed of upstream be X km/hr.

Then, speed in downstream = 2X km/hr (since boat takes twice as much as time to cover up than as to cover down the same distance in running water).

Speed in still water = (2X+X)/2 km/hr. (formula 3)
= 3X/2 km/hr.

Given that, boat covers 10 1/3 km in 1 hour in still water.

Therefore, 3X/2 = 10 1/3
X = 62/9

So, speed in upstream = 62/9 km/hr.
And, speed in downstream = 2 x 62/9 = 124/9 km/hr

Hence, speed of the current = [(124/9 - 62/9)]/2 km/hr
= 62/9x2 = 34/9 = 3 4/9 km/hr.

Question 2

A man can row a certain distance downstream in 2 hours while he takes 3 hours to come back. If the speed of the stream be 6 km/hr then the speed of the man in still water is:

a) 15km/hr b) 30km/hr c) 25km/hr d) 29km/hr

Answer : b) 30km/hr

Solution :

Let the speed of the man in still water be X km/hr.

Given that, speed of the stream = 6 km/hr.
Therefore, speed in downstream = (X+6) km/hr (by using formula 2)
And, speed in upstream = (X-6) km/hr

Distance covered in downstream in 2 hours = (X+6)2 km

Distance covered in upstream in 3 hours = (X-6)3 km

Therefore, (X+6)2 = (X-6)3
2X+12 = 3X-18
X = 30km/hr.

Question 3

A man can take the same time to row 13 km downstream and 7 km upstream. His speed in still water 5 km/hr. The speed of the stream is:

a) 5/2 km/hr b) 3/2 km/hr c) 7/2 km/hr d) 2 km/hr

Answer : b) 3/2 km/hr

Solution :

Given that, the speed in still water = 5 km/hr
Let the speed of the stream be X km/hr.
Then speed in downstream = (5+X) km/hr
And, speed in upstream = (5-X) km/hr

The time taken to cover 13 km downstream = 13/(5+X)
The time taken to cover 7 km upstream = 7/(5-X)

Therefore, 13/(5+X) = 7/(5-X)
13(5-X) = 7(5-X)
65 - 13X = 35+7X
30 = 20X
X = 30/20 = 3/2

Hence the required answer is 3/2 km/hr.

Question 4

A boat takes 7 hours to cover 24 km distance and comes back. And, it can cover 2 km with the stream in the same time as 1.5 km against the stream. The speed of the stream is:

a) 1 km/hr b) 2 km/hr c) 3 km/hr d) 4 km/hr

Answer : a) 1 km/hr

Solution :

Let the boat takes X hours to cover 2 km in downstream.
Then, speed in downstream = (2/X) km/hr

and, speed in upstream = (1.5/X)km/hr

Given that, the boat takes 7 hours to cover 24 km distance and comes back.

That is, 24/(2/X) + 24/(1.5/X) = 7
24X/2 + 48X/3 = 7
168X/6 = 7
X = 42/168 = 1/4

So, speed in downstream = 2/X = 2 /(1/4) = 8 km/hr
Speed in upstream = 1.5/X = 1.5 /(1/4) = 6 km/hr.

Speed of the stream = (8-6)/2 km/hr (by using the formula 3)
= 1 km/hr.

Question 1

The average of five consecutive odd integers is 113. What is the second smallest of them?

a) 111 b) 115 c) 109 d) none of these

Answer : a) 111

Solution :

Let the five consecutive odd numbers be X, X+2, X+4, X+6 and X+8

Given that, their average = 113.

That is, (X + X+2 + X+4 + X+6 + X+8) / 5 = 113
(5X + 20) / 5 = 113
5(X+4) / 5 = 113
X = 113 - 4 = 109.

Second smallest number is X + 2 = 109+2 = 111.

Hence the required number is 111.

Question 2

The average of 6 consecutive even numbers is 207. What will be the sum of the smallest and largest number?

a) 210 b) 408 c) 414 d) 208

Answer : c) 414

Solution :

Let the six consecutive odd numbers be X, X+2, X+4, X+6, X+8 and X+10

Given that, their average = 207

That is, (X + X+2 + X+4 + X+6 + X+8 + X+10)/6 = 207
(6X+30) / 6 = 207
6(X+5) / 6 = 207
X+5 = 207
X = 202.

Therefore the smallest number = 202 and the largest number = x+10 = 202+10 = 212

Required sum = 202+212 = 414.

Question 3

The average of the four consecutive even integers is 3645 less than their sum. What is the last of these numbers?

a) 1218 b) 2146 c) 3212 d) none of these

Answer : a) 1218

Solution :

Let the 4 consecutive even integers be X, X+2, X+4 and X+6.

Then, their average = (X + X+2 + X+4 + X+6)/4 = (4X+12)/4 = (X+3) ....(1)
And, their sum = (X + X+2 + X+4 + X+6) = 4X+12...(2)

Given that, average is 3645 less than the sum.

That is, from (1) and (2), 4x+12 = 3645 + X+3
3X = 3636
X = 1212

Therefore, required last number = X+6 = 1212 + 6 = 1218.

Question 4

If the average of seven consecutive odd numbers is 2117 then what will be the average of first four?

a) 2111 b) 2112 c) 2113 d) 2114

Answer : d) 2114

Solution :

Let the 7 consecutive odd numbers be X, X+2, X+4, X+6, X+8, X+10 and X+12.

We have to find the average of X, X+2, X+4 and X+6

That is, (X + X+2 + X+4 + X+6) / 4 = (4X+12) / 4 = X+3 ...(1)

Given that, the average that 7 numbers = 2117

That is, (X + X+2 + X+4 + X+6 + X+8 + X+10 + X+12)/7 = 2117
(7X + 42) / 7 = 2117
(X + 6) = 2117
X = 2111

Putting the above X value in (1), we get, X+3 = 2111+3 = 2114

Hence the required answer is 2114.

1. Downstream/Upstream:

In water, the direction along the stream is called downstream. And, the direction against the stream is called upstream.

If the speed of a boat in still water is u km/hr and the speed of the stream (or current) is v km/hr, then:

(i). Speed downstream = (u + v) km/hr.

(ii). Speed upstream = (u - v) km/hr.

2. If the speed downstream is a km/hr and the speed upstream is b km/hr, then:

(i). Speed in still water = (a + b)/2 km/hr.

(ii). Rate of stream = (a - b)/2 km/hr.

Question 1

The rate of current and boat in still water is 3 km/hr and 18 km/hr respectively.The boat starts from the point A and reaches the destination point B and returns back to A.Find the time taken by the boat for both forward and backward journey if the distance between them is 210 km.

a) 12 hours b) 20 hours c) 24 hours d) 16 hours

Answer : c) 24 hours.

Solution :

Speed of the stream = v = 3 km/hr
Speed of the boat in still water = u = 3 km/hr
Speed of the boat in downstream = (u + v) = 18 + 3 = 21 km/hr
Speed of the boat in upstream = (u - v) = 18 - 3 = 15 km/hr.

Distance between A and B = 210 km.
Time taken by the boat to reach B (forward journey) (in upstream) = distance/speed = 210/15 hours.
Time taken by the boat to reach A (backward journey) (in downstream) = 210/21 hours.
Total time = 210/15 + 210/21 hours = 14 + 10 = 24 hours.

Question 2

If the speed of the stream is 6 km/hr and the speed of a man in still water is 20 km/hr, then the distance covered by the man downstream in 15 minutes is:

a) 3.5 km b) 4.5 km c) 6.5 km d) 5.5 km

Answer : c) 6.5 km

Solution :

Time taken by the man = 15 minutes = 15/60 hour.
Speed of the stream = v = 6 km/hr
Speed of the man in still water = u = 20 km/hr.
Speed of the man in downstream = 20 + 6 = u + v = 26 km/hr.
Distance Covered = time x speed = 26 x 15/60 km = 6.5 km.

Question 3

The speed of a motor-boat in still water is 12 km/hr and the speed of the current is 3 km/hr. If the boat takes 3 hours to arrive at a place and return back, then how far is the place?

a) 17 km b) 18 km c)19 km d) 20 km

Answer : a) 17 km.

Solution :

Speed of the stream = v = 3 km/hr
Speed of the motor-boat in still water = u = 12 km/hr
Speed of the boat in downstream = (u + v) = 12 + 3 = 15 km/hr
Speed of the boat in upstream = (u - v) = 12 - 3 = 9 km/hr

Time taken by the boat to arrive and return back = 3 hours.
Let the required distance be X km.
Time taken by the boat in downstream = X/15 hr.
Time taken by the boat in upstream = X/9 hr.
Total time = 3 = X/15 + X/9
(3X + 5X)/45 = 3
X = 135/8 = 16.875 km.
Hence the distance is 17 km (approximately).


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