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  #2  
16th October 2014, 09:45 AM
Super Moderator
 
Join Date: Apr 2013
Re: Model Papers for IIT-JEE Exam

As per your request here I am sharing the model question paper of IIT-JEE Exam



Q. 1 Let X be the energy needed to raise the temperature of 5 moles of nitrogen held at constant pressure by one degree. Let Y be the energy needed to raise 5 moles of carbon monoxide by one degree with the pressure held constant. What is the ratio X:Y?

5:7
1:1
7:5
7:9

Q. 2 The difference Cp - Cv is a constant. This constant is often called R, the universal gas constant. Which of the following is true given the data?

For a monoatomic gas, Cp = 3/2 R
For a diatomic gas, Cp = 3/2 R
For a monoatomic gas, Cv = 3/2 R
For a diatomic gas, Cv = 3/2 R

Q. 3 How much energy would be required to heat two moles of methane by one degree if the gas is kept at constant volume?

6.5 calories
8.5 calories
11 calories
13 calories

Q. 4 Which of the following is a possible explanation for the fact that Cp is always greater than Cv?

Some of the energy is used to expand the container in order to maintain constant pressure.
A rigid container does not conduct heat as well as one that can change shape.
There are generally more moles of gas when the pressure is kept constant than when the volume is kept constant.
There are generally fewer moles of gas when the pressure is kept constant than when the volume is kep constant.

Q. 5 A certain amount of energy, X, is sufficient to raise the temperature of 60 moles of argon by T degrees when the pressure is constant. How many moles of argon can be raised by T degrees with the same amount of energy X, if the volume is held constant?

30
50
75
100
  #3  
25th March 2015, 10:46 AM
Unregistered
Guest
 
Re: Model Papers for IIT-JEE Exam

Can you provide me the previous year question paper of IIT JEE exam as my Brother will be giving the exam this year and need it for preparation?
  #4  
25th March 2015, 10:49 AM
Super Moderator
 
Join Date: Apr 2013
Re: Model Papers for IIT-JEE Exam

Below I am providing you some questions of from question paper of IIT-JEE Exam and attaching a PDF attachment which has detail information regarding this that you can down load for free:


One end of a taut string of length 3m along the x axis is fixed at x=0.The speed of the waves in the string is 100 𝑛𝑛𝑠𝑠−1. The other end of the string is vibrating in the y direction so that stationary waves are set up in the string. The possible waveform(s) of these stationary waves is(are) (A)𝑦𝑦(𝑡&#119905=𝐴𝐴 sin𝜋𝜋𝜋𝜋6cos50𝜋𝜋𝜋𝑡𝑡3 (B)𝑦𝑦(𝑡&#119905=𝐴𝐴 sin𝜋𝜋𝜋𝜋3cos100𝜋𝜋𝑡𝑡3 (C) 𝑦𝑦(𝑡&#119905=𝐴𝐴 sin5𝜋𝜋𝜋𝜋6cos250𝜋𝜋𝑡𝑡3 (D) 𝑦𝑦(𝑡&#119905=𝐴𝐴 sin5𝜋𝜋𝜋𝜋2cos 250𝜋𝜋𝑡𝑡

A student is performing an experiment using a resonance column and a tuning fork of frequency 244𝑠𝑠−1. He is told that the air in the tube has been replaced by another gas (assume that the column remains filled with the gas). If the minimum height at which resonance occurs is (0.350±0.005) 𝑚𝑛𝑛, the gas in the tube is


Heater of an electric kettle is made of a wire of length L and diameter d. It takes 4 minutes to raise the temperature of 0.5kgwater by 40K. This heater is replaced by a new heater having two wires of the same material, each of length L and diameter 2d.The way these wires are connected is given in the options. How much time in minutes will it take to raise the temperature of the same amount of water by 40 K? (A)4 if wires are in parallel (B) 2 if wires are in series (C)1 if wires are in series (D)0.5 if wires are in parallel

During Searle’s experiment, zero of the Vernier scale lies between 3.20×10−2 𝑛𝑛 and 3.25×10−2 𝑛𝑛 of the main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between 3.20×10−2 𝑛𝑛 and 3.25×10−2 𝑛𝑛 of the main scale but now the 45th division of Vernier scale coincides with one of the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is 8×10−7𝑛𝑛2. The least count of the Vernier scale is 1.0×10−5 𝑛𝑛. The maximum percentage error in the Young’s modulus of the wire is





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