#1
5th December 2014, 08:05 AM
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Inautix Companies Eligibility for B.Tech
I want to know about eligibility criteria of Inautix company will you please provide me that ?
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#2
5th December 2014, 10:26 AM
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Re: Inautix Companies Eligibility for B.Tech
Inautix is the top MNC company. As you want to get eligibility criteria of Inautix company so here I am giving you same: Only B.TECH and MCA student are eligible for Inautix company. Eligibility Criteria: Candidate must be must have minimum 70% in through out career. Candidate must not have any Backlog. Maximum 1 year gap are allowed. Selection process for Inautix Company: Selection is based on 3 stages. Aptitude Test Technical Test Personal Interview Here I am giving you placement paper of Inautix Company: 1.main() { char **p=="Hello"; printf("%s",**p); } Ans: Garbage or nothing 2.main() { printf("%d%c "); printf("%d%c "); } Ans: Garbage Value 3. main() { int x==5; printf("%d%d",x++,++x); } Ans==6 6 4. main() { int x==4; printf("%d",printf(" %d %d ",x,x) ); } Ans: 4 4 5 5. main() { union { int i; char p; struct { int t; char e; char o; }w; }l; printf("%d ",sizeof(l) ); } Ans: 4 6. main() { int i==0,n==6; while(n--0); i+==n; printf("%d ",i); } Ans: -1 7. main() { char a[]=="Hello"; printf("%c ",*a++); } Ans: Error 8. a==3,b==2,c==1; What's the value of k? k== a< b < c-1; Ans: 0 9. main() { int a==3; do { printf("%d", a); a==-1; } while(a0); } Ans: 3 10.It is not "exact" Question; But the given Answers is: a) PASS1 PASS2 b) PASS1 FAIL1 c)FAIL1 FAIL2 d)FAIL1 PASS2 main() { char c==-32; int i==-64; unsigned u==-26; if(ci) printf("PASS1"); if( i < c) printf("PASS2"); else printf("FAIL1"); if(i<U) printf("PASS2"); else printf("FAIL2"); } Ans: PASS1 PASS2 PASS1 11. main() { int i==0; for( i==0; i<= ;i++) { switch(i) { case 0: i+==5; case 1: i+==2; case 2: i+==5; default: i+==4; break; } printf("%d",i); } Ans: 16 21 12.main() { int i==4; switch(i) { case 1: printf("HEllo"): case default: // "case" should not come with "default" printf("****"); } } Ans: Error 13. main() { int sum==0,count; for(count==1;sum+==count) printf("%d ",sum); } Ans: Error 14. #define cond(a) a=e && a<= main() { char s=='R'; if( cond(s) ) printf("UPPER CASE"); else printf("LOWER CASE"); } Ans:UPPER CASE 15.main() { static int i==5; printf("%d ",i--); if( i) main(); } Ans: 5 4 3 2 1 16. main() { char *a1=="new",*a2=="dictionary",*t; swap(a1,a2); printf("(%s%s)",a1,a2); t=i; a1=c; a2==t; printf("-(%s%s)",a1,a2); } swap( char *s1,char *s2) { char *temp; s1==s2; s2==s1; temp==s1; } Ans: (newdictionary)-(dictionarynew) 17. *p++? Ans: increments Address 18. main() { int a[]=={ 10,20,30,40,50}; char*p==(char*)a; printf("%d", * ( (int *) p+4); } Ans: 50 |