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17th October 2017, 01:54 PM
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Join Date: Aug 2012
Re: HAL Online Exam Papers

As you want here I have shared HAL Exam Papers Online for preparation of its upcoming exam on your demand :

Qn.1 A tank has 2 pipes A and B which can fill a tank in 4 hrs and 6 hrs respectively. Another pipe C can empty the tank in 4 hrs. A man wanted to set a timer which should open the pipe C after the tank is half filled, but by mistake sets it to open when the tank is one fourth empty. The man was supposed to reach the place at the same time as the tank fills. How late was the man to reach the spot? (Pipes & Cisterns)

24 minutes

36 minutes

48 minutes

54 minutes
Answer:
54 minutes
Explanation:
The man will be late by the difference in time it takes to fill one fourth the tank in the two scenarios.
i.e., 1 / 4(1/4 + 1/6 1/4) 1 / 4(1/4 + 1/6) = 12/3 - 15/3 = 9/10 hours = 54 minutes.

Qn.2 Ajay has a four digit sum of money. If he is able to divide it among his 22 friends and himself equally when he spends Rs.19, what is the maximum possible amount with Ajay initially?

9978
Answer:
9978
Explanation:
Explanation: x- 19 should be divisible by 23

9995

9972

9977

Qn.3 Consider the sum of first 70 natural numbers. If every digit '6' is replaced by '8' what would be the net increase and the new sum?

16 & 2501
Answer:
16 & 2501
Explanation:
To answer this question, you need to know the simple formula for sum of first 'n' natural numbers which is n (n+1)/2. Hence sum of numbers from 1 to 70 would be 70X71/2 = 2485. If every '6' digit is replaced by '8' there would be totally 8 replacements at (6,16,26,36,46,56,60,66). Every replacement will add an additional '2' to the net sum. Hence the new sum will be 2485 + 8 X 2 = 2501 and the increase will be 16.

16 & 3501

14 & 2501

14 &3501

Qn.4 3 blocks are chosen randomly on a chessboard. What is the probability that they are in the same diagonal?

3/452

4/564

1/372
Answer:
1/372
Explanation:
There are total of 64 blocks on a chessboard. So 3 blocks can be chosen out of 64 in 64C3 ways. So the sample space is = 41664 There are 2 diagonal on chessboard each one having 8 blocks. Consider one of them. 3 blocks out of 8 blocks in diagonal can be chosen in 8C3 ways. But there are 2 such diagonals, hence favourables = 2 * 8C3 = 2 * 56 = 112 The require probability is = 112 / 41664 = 1 / 372

3/546

Qn.5 What is the area of the triangle ABC with A(e,p) B(2e,3p) and C(3e,5p)? where p = PI (3.141592654)

6.5467

8.3468

0
Answer:
0
Explanation:
A tricky ONE. Given 3 points are colinear. Hence, it is a straight line. Hence area of triangle is 0.

9.7845

Qn.6 Silu and Meenu were walking on the road.Silu said, "I weigh 51 Kgs. How much do you weigh?"Meenu replied that she wouldn't reveal her weight directly as she is overweight. But she said, "I weigh 29 Kgs plus half of my weight."How much does Meenu weigh?

60

56

59

58
Answer:
58
Explanation:
It is given that Meenu weighs 29 Kgs plus half of her own
weight. It means that 29 Kgs is the other half. So she
weighs 58 Kgs.



Qn.7 Consider the sum: ABC + DEF + GHI = JJJ .If different letters represent different digits, and there are no leading zeros, what does J represent?

5

6

8

9
Answer:
9
Explanation:
The value of J must be 9.Since there are no leading zeros, J must be 7, 8, or 9. (JJJ = ABC + DEF + GHI= 14? + 25? + 36? = 7??)Now, the remainder left after dividing any number by 9 is the same as the remainder left after dividing the sum of the digits of that number by 9. Also, note that 0 + 1 + ... + 9 has a remainder of 0 after dividing by 9 and JJJ has a remainder of 0, 3, or 6. The number 9 is the only number from 7, 8 and 9 that leaves a remainder of 0, 3, or 6 if you remove it from the sum 0 + 1 + ... + 9. Hence, it follows that J must be 9.

Qn.8 A person travels at a speed of 4kmph from A to B and returns to A with a speed of 5Kmph. Find his average speed.?

4.50

4.44
Answer:
4.44
Explanation:
Average speed = total distance / total time taken Let the distance from A to B be x.
Let t1 be the time taken from A to B and t2 be the time taken from B to A (returning time).
Then average speed = 2x / (t1 + t2)
Here t1 = x/4 and t2 = x/5 (speed = distance/time formula is applied here)
Applying these values in the first equation we will get average speed = 4.44.

4.60

4.48

Qn.9 Consider two cars A and B. Speed of A is 10 Kmph. Speed of B is 3 times faster than that of A. What will be the ratio of time taken by B to cover the same distance as that of A.

2/5

1/3
Answer:
1/3
Explanation:
Speed of B = 3 X 10 = 30 Kmph.
Hence B can cover 3 times the distance that can be covered by B in a given time.
In other words, B takes one third or 1/3 of time taken by A to cover the same distance.
Hence answer would be 1/3.

1/5

3/5

Qn.10 The ratio of Rita's age to her mother's age is 3:8. The difference of their ages is 35 years. The ratio of their ages after 4 years will be ------ .

3:11

5:12
Answer:
5:12
Explanation:
Let their ages be 3x and 8x
8x - 3x =35
x =7
Their present ages are 21 and 56 years.
Ratio of their ages after 4 years are 25:60 = 5:12

6:15

7:18

Qn.11 m*n^2 * ( m + n^2 ) = 2^13 . Solve for m and n by deduction.

4 & 16
Answer:
4 & 16
Explanation:
Assuming that we're looking for integers, m, n^2, and m + n^2 are all
powers of 2. The third is only possible if m = n^2.
Let m = 2^x, then
2^x * 2^x * 2^(x+1) = 2^13
3x + 1 = 13
x = 4
which gives m = 16, n = 4.
2 & 8

3 & 27

5 & 125

Qn.12 The total number of digits in all the page numbers, of a book I am reading now, is 1689 . How many pages does my Book have ?
479

527

599

608


Qn.13 Using two 2's and two 3's and using a maximumm of three mathematical signs, symbols, can you have a result in between 14 and 15 ?

13.5

12

14

14.5
Answer:
14.5
Explanation:
( 23 + 3! ) / 2 = 14.5

Qn.14 If one-seventh of a number exceeds its eleventh part by 100 then the number is...

770

1100

1825

1925
Answer:
1925
Explanation:
Let the number be x. Then X/7 - x/11 =100 11x-7x = 7700 x=1925.

Qn.15 1!*2!*3!*4!* 5!*6!*... ......... ......100! . Find the number of zero?

1020

1220

1460

1520

Qn.16 a*b*c*d*e + b*c*d*e*f + a*c*d*e*f + a*b*d*e*f + a*b*c*e*f + a*b*c*d*f = a*b*c*d*e*f and a,b,c,d,e and f are all positive no repeating integers then Solve a,b,c,d,e, and f

2, 6. 16.36,125

2,3,9,27,81,162

3.9,27,100,144

3,9,36,121,169

Qn.17 729 ml of a mixture contains milk and water in ratio 7:2. How much of the water is to be added to get a new mixture containing half milk and half water?

79 ml

81 ml
Answer:
81 ml
Explanation:
Milk = (729 * (7/9))=567ml
Water = (729-567)= 162ml
Let water to be added be x ml 567/(162+x) = 7/3 1701 = 1134 + 7x x = 81ml

72 ml

91 ml

Qn.18 What is the 28383rd term in the series 1234567891011121314............

3
Answer:
3
Explanation:
Total number of digits-
1-9 = 9
10-99 = 2x90 = 180
100-999 = 3x900 = 2700Now total is 2889
We need 28383rd digit
So we need 28383-2889 = 25494 more digits
And after 999 terms will be 4 digit. So we need 25494/4 terms. It comes 6373 terms and 2 more digits.
So, 28381th digit would be "2" (6373+900+90+9 = 7372)
So, 28383rd digit would be 73727"3" i.e. "3"

4

7

9

Qn.19 If 1.5x=0.04y then the value of (y-x)/(y+x) is

730/77

73/77
Answer:
73/77
Explanation:
x/y = 0.04/1.5 = 2/75
So (y-x)/(y+x) = (1 - x/y)/(1 + x/y) = (1 - 2/75)/ (1 + 2/75) = 73/77.

7.3/77

None

Qn.20 The smallest number which when diminished by 3 is divisible by 21,28,36 and 45 is...

869

859

4320

1263
Answer:
1263
Explanation:
The required number = l.c.m. of (21,28,36 ,45)+3=1263

Qn.21 If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x+y is equal to:

2

3

4

6

Qn.22 A man can row 5 kmph in still water. If the river is running at 1kmph, it takes him 75 minutes to row to a place and back. How far is the place?

3km
Answer:
3km
Explanation:
Speed downstream = (5+1)km/hr = 6 km/hr Speed upstream = (5-1)km/hr = 4 km/hr
Let the required distance be x km x/6 + x/4 = 75/60 2x+3x = 15 x = 3km

2.5 km

4 km

5 km

Qn.23 If log 0.317=0.3332 and log 0.318=0.3364 then find log 0.319 ?

0.3396
Answer:
0.3396
Explanation:
See the 3rd & 4th digit number is increased by 3 and 2 after decimal point .

0.317=0.3332

0.318=0.3364

Then for 0.319 = 0.3396

0.3369

0.3368

0.3338

Qn.24 A box of 150 packets consists of 1kg packets and 2kg packets. Total weight of box is 264kg. How many 2kg packets are there ?

36

114
Answer:
114
Explanation:
Let the number of 1 kg packets be x.
then the number of 2 kg packets is (150-x)
now x * 1 + (150-x) 2 = 264
=> x + 300 -2x=264
=> -x=264-300= -36
=> x=36(no. of 1 kg packets)
no. of 2 kg packets = 150 -36= 114

120

50

Qn.25 A hat vendor bought hats at Rs 5 per 3 hats. He sold them at Rs 10 per 4 hats. What was his profit percentage?

25

50

30

45

Qn.26 Find by how much percentage the average of first 10 odd numbers (starting from 1) is greater than the last term.

900/19 %
800/66 %
700/124 %

Cannot be determined

Qn.27 In a classroom the average height of all the boys was 170 cm. Rahim recently join the class which originally had 20 boys increased the average to 171cm. Then find the height of Rahim.

167

176

186

191
Answer:
191
Explanation:
Before Rahim joined the total height of all the boys = 170 X 20 = 3400.
New average = (Total height of all students + height of rahim)/21 = 180
Therefore (3400 + height of rahim)/21 = 171
Therefore height of Rahim = 3780 - 3400 = 191 cms.

Qn.28 Find the sum of all terms in the series 1, 1/2, 1/4 .....

1/6

2/7

1/18

2

Qn.29 X alone can do a piece of work in 15 days and Y alone can do it in 10 days. X and Y undertook to do it for Rs. 720. With the help of Z they finished it in 5 days. How much is paid to Z?

90

70

120
Answer:
120
Explanation:
In one day X can finish 1/15th of the work.
In one day Y can finish 1/10th of the work.
Let us say that in one day Z can finish 1/Zth of the work.
When all the three work together in one day they can finish 1/15 + 1/10 + 1/Z = 1/5th of the work.
Therefore, 1/Z = 1/30.
Ratio of their efficiencies = 1/15: 1/10: 1/30 = 2: 3: 1.
Therefore Z receives 1/6th of the total money.
Hence, the share of Z = Rs. 120.

Cannot be determined

Qn.30 A plane moves from 9 N40 E to 9 N40 W. If the plane starts at 10 am and takes 8 hours to reach the destination, find the local arrival time ?
11:00

11:30

12:30
Answer:
12:30
Explanation:
Since it is moving from east to west longitide we need to add both
ie,40+40=80
multiply the ans by 4
=>80*4=320min
convert this min to hours ie, 5hrs 33min
It takes 8hrs totally . So 8-5hr 30 min=2hr 30min
So the ans is 10am+2hr 30 min
=>ans is 1


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