Tips to Solve numerical problems Faster

How I become master to solve the numerical problems faster with accuracy?

[Raman Vij]

I would like to give some tips to crack numerical problem faster and with accuracy. Please give some attention to following points.

Firstly, practice more mathematical questions.
Learn some shortcuts
Read carefully the questions.
You have common formulas on your tips.
Whenever you are practicing, keep watch with you so you know how much time you are taken to solve the questions and try to make the time shorter day by day.

Keep attention on following topics for your practice

Numbers
Ratio, Proportion, Variation
Averages,Mixtures and Alligation
Time,Speed and Distance
Time and Work
Percentages
Profit and Loss
Simple and Compound Interest
Fractions
Partnership
Progression
Permutation and Combination
Probability
Geometry and Mensuration
Simplification
Boats and Streams
Surds and Indices
Number System
Sets and Union
Logarithm

Here, I am giving the some sample question with answer for your considerations.

The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
A 1677
B 1683
C 2523
D 3363

Answer: Option B
Explanation:
L.C.M. of 5, 6, 7, 8 = 840. Required number is in the of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k= 2.
Required number = (840*2+3) = 1683.

There is a certain four digit number whose fourth digit is twice the first digit. Third digit is three more than second digit. Sum of the first and fourth digits is twice the third number. What was that number?
A 3036
B 4368
C 4148
D 3146

Answer: Option B
Explanation:
From the options, only 4368 is satisfying the conditions
As per First condition; 4*2 = 8
As per second condition 3+3 = 6
As per third condition 4+8 = 2*6






If the number 42573 * is exactly divisible by 72, then the minimum value of * is:
A 4
B 5
C 6
D 7

Answer: Option C
Explanation:
72 = 9 x8, where 9 and 8 are co-prime.
The minimum value of x for which 73x for which 73x is divisible by 8 is, x = 6.
Sum of digits in 425736 = (4 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 9.
Required value of * is 6.

A number which when divided by 3, 4, 5, 6, 7, leaves the remainder 2, 3, 4, 5 and 6 respectively. Such largest 5 digit number is :
A 99960
B 999579
C 99539
D 99959

Answer: Option D
Explanation:
Observe that 3-2.4-3…7-6 leave 1 as the common difference
LCM (3, 4, 5,6, 7) = 3*4*5*7 = 420
Largest 5 digits number = 99999, Which on being divided by 420 will leave 238 and 39 as remainder
Hence, the largest such number = 99999-(remainder + common difference) = 99999-40 =99959.

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
A 4
B 5
C 6
D 8

Answer: Option A
Explanation:
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305) = H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Here, I am giving the PDF for more question. practice these PDF

Sample Paper For numerical problems

sir i can't able to solve numerical mostly in physic i am so losser in mathematics so how can i improve this problem