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  #1  
18th January 2017, 11:19 AM
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Quadratic Equation For SSC CGL

Hello sir, is there any one can provide me here some questions for Quadratic Equation For SSC CGL?
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  #2  
18th January 2017, 11:47 AM
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Join Date: Aug 2012
Re: Quadratic Equation For SSC CGL

As you want here I’m giving you some Questions from quadratic equations are being asked in Bank PO.

Here are some Questions from quadratic equations are being asked in SSC CGL:

Questions from quadratic equations are being asked in SSC CGL:

1.I. 20a^2 + 51a + 28 = 0
II. 15b^2 − 61b + 56 = 0
1 : if a > b
2 : if a < b
3 : if a ≥ b
4 : if a ≤ b
5 : if a = b or the relation between a and b cannot be established.

2.I. 2a^2 − 11a + 12 = 0
II. 35b^2 − 18b − 8 = 0
1 : if a > b
2 : if a < b
3 : if a ≥ b
4 : if a ≤ b
5 : if a = b or the relation between a and b cannot be established.

3.I. 28a^2 + 25a − 8 = 0
II. 5b^2 − 13b − 6 = 0
1 : if a > b
2 : if a < b
3 : if a ≥ b
4 : if a ≤ b
5 : if a = b or the relation between a and b cannot be established.

4.I. 12a^2 − a − 6 = 0
II. 8b^2 − 26b + 15 = 0
1 : if a > b
2 : if a < b
3 : if a ≥ b
4 : if a ≤ b
5 : if a = b or the relation between a and b cannot be established.

5.I. 32a^2 + 52a + 15 = 0
II. 8b^2 + 38b + 35 = 0
1 : if a > b
2 : if a < b
3 : if a ≥ b
4 : if a ≤ b
5 : if a = b or the relation between a and b cannot be established.

6.I. 6x^2 – 71x + 195 = 0
II. 12y^2 – 97y + 195 = 0
1 : if x ≥ y
2 : if x ≤ y
3 : if x > y
4 : if x < y
5 : if x = y or relationship cannot be established

7.I. 56x^2 – 127x + 72 = 0
II. 6y^2 – 17y + 12 = 0
1 : if x ≥ y
2 : if x ≤ y
3 : if x > y
4 : if x < y
5 : if x = y or relationship cannot be established

8.I. 3x^2 – 47x + 184 = 0
II. 3y^2 – 38y + 119 = 0
1 : if x ≥ y
2 : if x ≤ y
3 : if x > y
4 : if x < y
5 : if x = y or relationship cannot be established

9.I. 20x^2 – 119x + 176 = 0
II. 18y^2 – 123y + 209 = 0
1 : if x ≥ y
2 : if x ≤ y
3 : if x > y
4 : if x < y
5 : if x = y or relationship cannot be established

10.I. 63x^2 – 275x + 300 = 0
II. 18y^2 – 85y + 100 = 0
1 : if x ≥ y
2 : if x ≤ y
3 : if x > y
4 : if x < y
5 : if x = y or relationship cannot be established

Questions from quadratic equations are being asked in Bank SSC CGL.

In each of the following questions two equations are given. Solve these equations and give answer :
A) if x >= y, i.e x is greater than or equal to y
B) if x > y, i.e x is greater than y
C) if x <= y, i.e x is less than or equal to y
D) if x < y, i.e x less than y
E) if x = y,or no relation can be established between x and y

1. I.x2 + 5 x + 6 = 0
II.y2 +7 y + 12 = 0

2. I.x2 + 20 = 9x
II.y2 + 42 = 13y

3. I.2x + 3y = 14
II. 4x + 2y = 16

4. I.x = Sqrt625
II.y = sqrt 676

5. I. x2 + 4x + 4 = 0
II.y2 – 8y + 16 = 0

6. I.x2 – 19x + 84 = 0
II.y2 – 25y + 156 = 0

7. I.x3 – 468 = 1729
II.y2 – 1733 + 1564 = 0

8. I. 9/√x + 19/√x = √x
II.y5 – (2×14)11/2/√y = 0

9. I.√784x + 1234 = 1486
II. √1089y + 2081 = 2345

10. I.12/√x – 23/√x = 5√x
II.√y/12 -5√y/12 = 1/√y


ANSWERS with explanation
Answer 1.
I. x2 + 5x + 6 = 0
=>x2 + 2x + 3x + 6 = 0
=>x(x + 2) + 3(x + 2) = 0
=>(x + 3)(x + 2) =0
=> x= -3 or -2

II. y2+ 7y + 12 = 0
=>y2 + 4y + 3y + 12 = 0
=>y(y + 4) + 3 (y + 4) = 0
=>(y + 3) (y + 4) = 0
=> y = – 3 or – 4

Answer 2.
I. x2 – 9x + 20 = 0
x 2 – 5x – 4x + 20 = 0
x(x – 5) – 4 (x – 5) = 0
(x – 4) (x – 5) = 0
x = 4 or 5

II. y2 – 13 y + 42 = 0
=>y2 – 7y – 6y + 42 = 0
=>y(y – 7) – 6(y – 7) = 0
=>(y – 6) (y – 7) = 0
=> y = 6 or 7

Answer 3. 2x + 3y = 14….(i)
4x + 2y = 16….(ii)

On solving, (i) x 2 – (ii) we get,

4x + 6y – 4x – 2y = 28 – 16
=> 4y = 12 =>y = 3
So, the value of x will be –
2x + 3 x 3 = 14
=>2x = 14 – 9 = 5 => x = 5/2

Answer 4.
I. x = √625 = +25 or -25
II. y = √676 = +26 or -26

Answer 5.
I. x 2 + 4x + 4 = 0
(x + 2)2 = 0 => x = – 2

II. y2 – 8y + 16 = 0
=>(y – 4)2 = 0
=>y = 4

Answer 6.
I. x2 – 19 x + 84 = 0
=> x2 – 12 x – 7 x + 84 = 0
=> x(x – 12) – 7 (x – 12) = 0
=> (x – 7) (x – 12) = 0
So, x = 7 or x = 12

II. y2 – 25 y + 156 = 0
=> y2 – 12 y – 13 y + 156 = 0
=> y(y – 12) – 13 (y – 12) = 0
=> (y – 13) (y – 12) = 0
So, y = 12 or 13

Answer 7.
I. x3 = 1729 + 468 = 2197
So, x = 3√2197 = 13

II. y2 = 1733 – 1564 = 169
So, y = √169 = + 13 or – 13

Answer 8.
I. 9 + 19 = √x + √x
=> 28 = x

II. y 5 x y1/2 = (28)11/2
=> y11/2 = (28)11/2
=> y = 28

Answer 9. I. √784 x = 1486 – 1234 = 252
=> x = 252/√784 = 252/28 = 9

II. √1089y = 2345 – 2081 = 264
=>y = 264/√1089 = 264/33 = 8

Answer 10.
I. 12 – 23 = 5 √x x √x
=>-11 = 5x
=>x = -11/5

II. (√y – 5√y)/12 = 1/√y
=> -4√y x √y = 12
=> -4y = 12
=> y = -3


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