#1
18th January 2017, 11:19 AM
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Quadratic Equation For SSC CGL
Hello sir, is there any one can provide me here some questions for Quadratic Equation For SSC CGL?
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#2
18th January 2017, 11:47 AM
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Re: Quadratic Equation For SSC CGL
As you want here I’m giving you some Questions from quadratic equations are being asked in Bank PO. Here are some Questions from quadratic equations are being asked in SSC CGL: Questions from quadratic equations are being asked in SSC CGL: 1.I. 20a^2 + 51a + 28 = 0 II. 15b^2 − 61b + 56 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established. 2.I. 2a^2 − 11a + 12 = 0 II. 35b^2 − 18b − 8 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established. 3.I. 28a^2 + 25a − 8 = 0 II. 5b^2 − 13b − 6 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established. 4.I. 12a^2 − a − 6 = 0 II. 8b^2 − 26b + 15 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established. 5.I. 32a^2 + 52a + 15 = 0 II. 8b^2 + 38b + 35 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established. 6.I. 6x^2 – 71x + 195 = 0 II. 12y^2 – 97y + 195 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established 7.I. 56x^2 – 127x + 72 = 0 II. 6y^2 – 17y + 12 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established 8.I. 3x^2 – 47x + 184 = 0 II. 3y^2 – 38y + 119 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established 9.I. 20x^2 – 119x + 176 = 0 II. 18y^2 – 123y + 209 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established 10.I. 63x^2 – 275x + 300 = 0 II. 18y^2 – 85y + 100 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established Questions from quadratic equations are being asked in Bank SSC CGL. In each of the following questions two equations are given. Solve these equations and give answer : A) if x >= y, i.e x is greater than or equal to y B) if x > y, i.e x is greater than y C) if x <= y, i.e x is less than or equal to y D) if x < y, i.e x less than y E) if x = y,or no relation can be established between x and y 1. I.x2 + 5 x + 6 = 0 II.y2 +7 y + 12 = 0 2. I.x2 + 20 = 9x II.y2 + 42 = 13y 3. I.2x + 3y = 14 II. 4x + 2y = 16 4. I.x = Sqrt625 II.y = sqrt 676 5. I. x2 + 4x + 4 = 0 II.y2 – 8y + 16 = 0 6. I.x2 – 19x + 84 = 0 II.y2 – 25y + 156 = 0 7. I.x3 – 468 = 1729 II.y2 – 1733 + 1564 = 0 8. I. 9/√x + 19/√x = √x II.y5 – (2×14)11/2/√y = 0 9. I.√784x + 1234 = 1486 II. √1089y + 2081 = 2345 10. I.12/√x – 23/√x = 5√x II.√y/12 -5√y/12 = 1/√y ANSWERS with explanation Answer 1. I. x2 + 5x + 6 = 0 =>x2 + 2x + 3x + 6 = 0 =>x(x + 2) + 3(x + 2) = 0 =>(x + 3)(x + 2) =0 => x= -3 or -2 II. y2+ 7y + 12 = 0 =>y2 + 4y + 3y + 12 = 0 =>y(y + 4) + 3 (y + 4) = 0 =>(y + 3) (y + 4) = 0 => y = – 3 or – 4 Answer 2. I. x2 – 9x + 20 = 0 x 2 – 5x – 4x + 20 = 0 x(x – 5) – 4 (x – 5) = 0 (x – 4) (x – 5) = 0 x = 4 or 5 II. y2 – 13 y + 42 = 0 =>y2 – 7y – 6y + 42 = 0 =>y(y – 7) – 6(y – 7) = 0 =>(y – 6) (y – 7) = 0 => y = 6 or 7 Answer 3. 2x + 3y = 14….(i) 4x + 2y = 16….(ii) On solving, (i) x 2 – (ii) we get, 4x + 6y – 4x – 2y = 28 – 16 => 4y = 12 =>y = 3 So, the value of x will be – 2x + 3 x 3 = 14 =>2x = 14 – 9 = 5 => x = 5/2 Answer 4. I. x = √625 = +25 or -25 II. y = √676 = +26 or -26 Answer 5. I. x 2 + 4x + 4 = 0 (x + 2)2 = 0 => x = – 2 II. y2 – 8y + 16 = 0 =>(y – 4)2 = 0 =>y = 4 Answer 6. I. x2 – 19 x + 84 = 0 => x2 – 12 x – 7 x + 84 = 0 => x(x – 12) – 7 (x – 12) = 0 => (x – 7) (x – 12) = 0 So, x = 7 or x = 12 II. y2 – 25 y + 156 = 0 => y2 – 12 y – 13 y + 156 = 0 => y(y – 12) – 13 (y – 12) = 0 => (y – 13) (y – 12) = 0 So, y = 12 or 13 Answer 7. I. x3 = 1729 + 468 = 2197 So, x = 3√2197 = 13 II. y2 = 1733 – 1564 = 169 So, y = √169 = + 13 or – 13 Answer 8. I. 9 + 19 = √x + √x => 28 = x II. y 5 x y1/2 = (28)11/2 => y11/2 = (28)11/2 => y = 28 Answer 9. I. √784 x = 1486 – 1234 = 252 => x = 252/√784 = 252/28 = 9 II. √1089y = 2345 – 2081 = 264 =>y = 264/√1089 = 264/33 = 8 Answer 10. I. 12 – 23 = 5 √x x √x =>-11 = 5x =>x = -11/5 II. (√y – 5√y)/12 = 1/√y => -4√y x √y = 12 => -4y = 12 => y = -3 |