#1
25th September 2014, 08:52 AM
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Mahadiscom Exam Syllabus For Electrical Sub Engineer
Will you please provide the Mahadiscom Exam Syllabus For Electrical Sub Engineer ?
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#2
25th September 2014, 10:12 AM
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Re: Mahadiscom Exam Syllabus For Electrical Sub Engineer
Here I am providing the Maharashtra State Electricity Distribution Company Limited syllabus for professional examination for Electrical Sub Engineer, the exam is divided into following sections: Transmission of Electricity. National Electricity Policy and Plan. Tariff. Generation of Electricity. Central Electricity Authority. Regulatory Commission. Elements of Double Entry. Rules of Journalising. Ledger Accounts. Sub Divisions of Journal. Cash Book. Appellate Tribunal for Electricity. Reorganisation of Board. Miscellaneous. Banking Transactions. Dishonor of bills payable, retiring bills payable under Discount Foreign and documentary bills. Bill Transactions-Acceptance of Bills, dishonor of bills, Notice and protesting, Discounting Bills, renewal of Bills, Bills payable Accounts. For detailed information , here is the attachment |
#3
21st March 2015, 08:29 AM
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Re: Mahadiscom Exam Syllabus For Electrical Sub Engineer
Will you provide me the Syllabus For Electrical Sub Engineer exam conducted by Mahadiscom as I am looking for the same ?
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#4
21st March 2015, 08:31 AM
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Re: Mahadiscom Exam Syllabus For Electrical Sub Engineer
As you want I am here providing you syllabus For Electrical Sub Engineer exam conducted by Mahadiscom. Electrical Engineering Basic Electrical Engg. & Electt. Measurements Concepts of currents Voltage Resistance Power and energy Their units Ohm's law. Circuit Law: Kirchhoff’s law Solution of simple network problems Network theorems and their applications Electro-magnetism concept of flux Emf Reluctance Magnetic circuits Electro-magnetic induction Self and mutual inductance. A.C. fundamentals Instantaneous Peak R.m.s. And average values of alternating waves Equation of sinusoidal wave form Simple series and parallel a.c. Circuits consisting of R.L. and C. Resonance Measurement and measuring instruments Moving coil and moving iron ammeters and voltmeters Extension of range Watt meters Multimeters Megger Basic Electronics Electrical machines Basic principles D C motors of generators Their characteristics Speed control and starting of D.C. motors Losses and efficiency of D.C. machines. 1-phase and 3-phase Transformers Principles Of Operation Equivalent Circuit Voltage Regulation O.C. And S.C. Tests Efficiency Auto Transformers Synchronous Machines Generation Of Three Phase Emf Armature Reaction Voltage Regulation Parallel Operation Of Two Alternators Synchronizing Staring And Applications Of Synchronous Motors 3-Phase Induction Motor Rotating Magnetic Field Principle Of Operation Equivalent Circuit Torque Speed Characteristics Starting And Speed Control Of 3-Phase Induction Motors Fractional Kw Motors 1-Phase Induction Motors A.C. Series Motor Reluctance Motor General, Transmission and Distribution Different types of power stations Load factor Diversity factor Demand factor Simple problems thereon Cost of generation inter connection of power stations Power factor improvement Various types of tariffs Types of faults Short circuit current for symmetrical faults Switchgears-rating of circuit breakers: - Principles of a are extinction by oil and air - H.R.C. fuses - Protection earthier leakage - Over current Buchhotgz relay - Merz-Prince system of protection of generators & transformers - Protection of feeders and bus bars. - Lightning arresters - Various transmission and distribution systems - Comparison of conductor materials - Efficiency for different systems. Utilization of Electrical Energy Illumination Electric heating Electric welding Electroplating Electric drivers and motors Sample paper Electrical – Mahadiscom exam 1. Find the Fourier sine transform of f(x), where f(x) = f(x) 1,0<x<a { 0, x>a (a) √2/p (cos st / s) (b) √2/p (1 - cos as / s) (Ans) (c) √2 (1 - cos as) (d) None of these 2. A random variable X with uniform density in the interval 0 to 1 is Quantized as follows: If 0 ≤ X ≤ 0.3, xq = 0 If 0.3 ≤ X ≤ 1, xq = 0.7 Where Xq is the quatized value of x The root mean square value of the quantization noise is (a) 0.573 (b) 0.198 (ans) (c) 2.205 (d) 0.266 Solution : Since it is uniform as xq = 0 in the range 0≤x≤0.3 xq = 0.7 in the range 0.3≤x≤1 The square mean value is ¥ s2 = ∫ (x - xq)2 f (x) dx -¥ 1 = ∫ (x - xq)2 f (x) dx 0 0.3 0.1 = ∫ (x - 0)2 f (x) dx + ∫ (x - 0.7)2 f (x) dx 0 0.3 0.3 1 = [x3/3] + [x3/3 + 0.49 x - 1.4] 0 0.3 or s2 = 0.039 The root mean square quantization noise RMS = √s2 = √0.039 = 0.198 3. Choose the correct one from among the alternatives A, B, C, D after matching an item from Group 1 with the most appropriate item in Group 2. Group 1 Group 2 1 : FM P : Slope overload 2 : DM Q : m Law 3 : PSK R : Envelope detector 4 : PCM S : Capture effect T : Hilbert transform U : Matched filter (a) 1 - T, 2 - P, 3 - U, 4 - S (b) 1 - S, 2U, 3 - P, 4 - T (c) 1 - S, 2 - P, 3U, 4 - Q (ans) (d) 1 - U, 2 - R, 3 - S, 4 - Q Solution : FM --- Capture effect --- Receives only strong signal DM ---- Slop over load Noise PSK --- Matched filter PCM - m law - Non linear quantization by using Companding with a law V = log (1 + m |M|) log (1 +m ) 4. There analog signals, having bandwidth 1200 Hz, 600 Hz and 600 Hz, are sampled at their respective Nyquist rates, encoded with 12 bit words, and time division multiplexed. The bit rate for the multiplexed signal is (a) 115.2 kbps (b) 28.8 kbps (c) 57.6 kbps (ans) (d) 38.4 kbps Solution : The three analog Signals having BW 1200 Hz, 600Hz and 600 Hz are sampled at their respective Nyquist rate i.e. at 2400, 1200, 1200 sample/sec respectively. The total of (2400 + 1200 + 1200) = 4800 sample/sec The Bit rate = n. fs = (4800 sample/sec) x 12 = 57.6 Kbps Where n = number of bit in a symbol 5. Find the correct match between group 1 and group 2. Ground I P - [1 + km (t)] A sin (wct) Q - km (t) A sin (wct) R - A sin [ w'c + k]'-¥ m (t) dt S - A sin [wct + k '∫-¥ m (t) dt] Solution : Group II W - Phase modulation X - Frequency modulation Y - Amplitude modulation Z - DSB-SC modulation P Q R S (a) Z Y X W (b) W X Y Z (c) X W Z Y (d) Y Z W X (ans) Solution : The correct match is given below [1 + km (t)] A sin (wct) Amplitude modulation km (t) A sin (wct) DB-SC modulation A sin [w'c + k]'-¥ m (t) dt Phase modulation A sin [wct + k '∫-¥ m (t) dt] Frequency modulation 6. Which of the following analog modulation scheme requires the minimum transmitted power and minimum channel bandwidth? (a) VSB (b) DSB-SC (c) SSB (ans) (d) AM Solution : VSB → fm + fc DBS - SC → 2 fm SSB → fm AM → 2 fm Thus SSB has minimum bandwidth and it required minimum power i.e. 17% as compared to AM. 7. A device with input x(t) and output y(t) is characteristic by : y (t) = x2(t). An FM signal with frequency deviation of 90 KHz and modulation signal bandwidth of 5 KHz is applied to this device. The bandwidth of the output signal is (a) 370 KHz (ans) (b) 190 KHz (c) 380 KHz (d) 95 KHz Solution : In present case ∆f = 90; fm = 5 β = [∆f / fm] = [90/5] = 18 FM equation A cos [wct + β = sin wmt] = A cos [wct + 18 sin wmt] y(t) = x2 (t) = A2 cos2 [wct + 18 Sin wmt] Note : Cos2 q = [1 + Cos2q] / 2 If there is change in frequency the modulation index also changes in same ratio y(t) = A2 [(1/2) + (1/2) Cos {2wct + 36Sin wmt}] y(t) = [(A2/2) + (A2/2) Cos {2wct + 36Sin wmt}] After the device, β(new) = 36 = [∆f(new) / fm] ∆f(new) = 36 x 5 = 180 By carson's rule Bandwidth = 2(∆f + fm) = 2 (180 + 5) Bandwidth = 370 kHz 9. A carrier is phase modulated (PM) with frequency deviation of 10 KHz by a single tone frequency of 1 KHz. If the single tone frequency is increased to 2 KHz, assuming that phase deviation remains unchanged, the bandwidth of the PM signal is (a) 21 kHz (b) 22 kHz (c) 42 kHz (d) 44 kHz (ans) Solution : ∆f = 10 KHz fm(new) = 2 KHz fm = 1 KHz By carson's Rule BW = 2 (∆f + fm) = 2 (10 + 1) = 22 KHz ∆ f(new) = 2 x 10 = 20 BW(new) = 2 (20 + 2) = 44 kHz 10 If A and B be the set and Ac and Bc denote the complements of the sets. A and B, then set (A - B) È (B - A) È (A Ç B) is equal to (a) A È B (Ans) (b) Ac È Bc (c) A Ç B (d) Ac Ç Bc 11 Let G = G(V, E) has five vertices, then the maximum number of m of edges in E, if G is a multigraph ? (a) 5 (b) 2 (c) 10 (d) Finite or infinite (Ans) 12 How many straight line can be drawn through 10 points on a circle ? (a) 10 (b) 20 (c) 45 (Ans) (d) Infinite 13 . The Fourier transform of unit step function u(t) is (a) 1 (b) pd(w) (c) pd(w) - 1/jw (Ans) (d) pd(w) + 1/jw 14. The value of the integral ∫ e-2(x - t) d(t - 2) dt is -∞ (a) e-2(x - 2) (Ans) (b) e2(x - 2) (c) e-2(x + 2) (d) e2(x + 2) 15. The uint of Ñ x H is (a) A (b) A/m (c) A/m2 (Ans) (d) A-m |
#5
13th May 2015, 10:56 PM
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my electrical syllabus completed......
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