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5th May 2016, 04:08 PM
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| Re: Life Science Syllabus National Eligibility Test
CSIR UGC NET is a national level examination which is schedules to be conducted in June and December every year. This examination gets conducted to select best candidates for eligibility of Assistant Professor and Junior Research Fellowship (JRF). Eligibility: You must have completed Master’s degree with minimum 55% marks. CSIR UGC NET Life Science Syllabus      Please find the below attached file for the CSIR UGC NET Life Science Syllabus: The Joint CSIR-UGC JRF/LS (NET) Examination shall comprise 2 papers: PAPER I: This paper shall be of 2 hours and 30 minutes duration and shall have a maximum of 200 marks. Part ‘A’ of Paper I shall contain 40 General Science questions. These questions shall be common to all subject areas of NET Examination. A candidate shall be required to answer a maximum of 25 questions from Part ‘A’. Part ‘B’ of Paper I shall have 100 questions. A candidate shall be required to answer a maximum of 75 questions. In case a candidate answers more than 75 questions, only the first 75 answered questions shall be evaluated. All questions shall be of two marks each. There will be negative marking for wrong answers. PAPER II: This paper shall be of 2 hours and 30 minutes duration and shall have a maximum of 200 marks This Paper shall consist of 39-45 short answer type questions requiring descriptive answers. To answer each question, a candidate will be provided one page each. Important Dates for UGC NET July 2016: Application process will be start from 12th April 2016 Last Date to apply for UGC NET June 2016 12th May 2016 Last date to pay application fee 13th May 2016 Correction in perticulars of application form 17th to 23rd May 2016 Date of the UG NET Examination 10th July 2016 |