Inautix Companies Eligibility for B.Tech

I want to know about eligibility criteria of Inautix company will you please provide me that ?

[Kiran Chandar]

Inautix is the top MNC company.
As you want to get eligibility criteria of Inautix company so here I am giving you same:

Only B.TECH and MCA student are eligible for Inautix company.

Eligibility Criteria:
Candidate must be must have minimum 70% in through out career.
Candidate must not have any Backlog.
Maximum 1 year gap are allowed.

Selection process for Inautix Company:
Selection is based on 3 stages.

Aptitude Test
Technical Test
Personal Interview

Here I am giving you placement paper of Inautix Company:

1.main()
{
char **p=="Hello";
printf("%s",**p);
}

Ans: Garbage or nothing


2.main()
{
printf("%d%c ");
printf("%d%c ");
}

Ans: Garbage Value


3. main()
{
int x==5;
printf("%d%d",x++,++x);
}
Ans==6 6


4. main()
{
int x==4;
printf("%d",printf(" %d %d ",x,x) );
}

Ans: 4 4 5


5. main()
{
union
{
int i;
char p;

struct
{
int t;
char e;
char o;
}w;

}l;

printf("%d ",sizeof(l) );

}

Ans: 4


6. main()
{
int i==0,n==6;
while(n--0);
i+==n;
printf("%d ",i);
}

Ans: -1

7. main()
{
char a[]=="Hello";
printf("%c ",*a++);
}
Ans: Error

8. a==3,b==2,c==1;
What's the value of k?
k== a< b < c-1;
Ans: 0


9. main()
{
int a==3;
do
{
printf("%d", a);
a==-1;
} while(a0);
}

Ans: 3

10.It is not "exact" Question; But the given Answers is:
a) PASS1 PASS2
b) PASS1 FAIL1
c)FAIL1 FAIL2
d)FAIL1 PASS2

main()
{
char c==-32;
int i==-64;
unsigned u==-26;
if(ci)
printf("PASS1");
if( i < c)
printf("PASS2");
else
printf("FAIL1");
if(i<U)
printf("PASS2");
else
printf("FAIL2");
}

Ans: PASS1 PASS2 PASS1

11.
main()
{
int i==0;
for( i==0; i<= ;i++)
{
switch(i)
{
case 0: i+==5;
case 1: i+==2;
case 2: i+==5;
default: i+==4;
break;
}
printf("%d",i);
}

Ans: 16 21


12.main()
{
int i==4;
switch(i)
{
case 1:
printf("HEllo"):
case default: // "case" should not come with "default"
printf("****");
}
}

Ans: Error

13.
main()
{
int sum==0,count;
for(count==1;sum+==count)
printf("%d ",sum);
}
Ans: Error


14.
#define cond(a) a=e && a<=
main()
{
char s=='R';
if( cond(s) )
printf("UPPER CASE");
else
printf("LOWER CASE");
}

Ans:UPPER CASE


15.main()
{
static int i==5;
printf("%d ",i--);
if( i)
main();
}

Ans: 5 4 3 2 1

16. main()
{
char *a1=="new",*a2=="dictionary",*t;
swap(a1,a2);
printf("(%s%s)",a1,a2);
t=i;
a1=c;
a2==t;
printf("-(%s%s)",a1,a2);
}

swap( char *s1,char *s2)
{
char *temp;
s1==s2;
s2==s1;
temp==s1;
}

Ans: (newdictionary)-(dictionarynew)

17.
*p++?
Ans: increments Address

18.
main()
{
int a[]=={ 10,20,30,40,50};
char*p==(char*)a;
printf("%d", * ( (int *) p+4);
}

Ans: 50