IIT JEE Shortcut Methods

Hii sir, I Am Preparing for the IIT JEE Examination I Wants to Know Some Shortcut Methods for Doing Calculation Faster for the Mathematic Section?

[pawan]

IIT JEE is Joint Entrance Exam that is Conducted for Admission Into the Undergraduate Engineer And Architecture Courses of the Colleges of India . The Examination is Conducted by CBSE .


MULTIPLICATION OF 11 WITH ANY NUMBER OF 3 DIGITS.

1.352*11 = 3---(3+5)---(5+2)---2 = 3872
Means insert the sum of first and second digits, then sum of second and third digits between the two terminal digits of the number
213*11 = 2---(2+1)---(1+3)---3 = 2343 EXAMPLE. Here an extra case arises

Consider the following examples for that

1) 329*11 = 3--- (3+2) +1--- (2+9-10) ---9 = 3619
Means, if sum of two digits of the number is greater than 10, then add 1 to previous digit and subtract 10 to the associated digit.
2)758*11 = 7+1---(7+5-10)+1---(5+8-10)---8 = 8338


TO CALCULATE REMINDER ON DIVIDING THE NUMBER BY 27 AND 37

consider number 34568276, we have to calculate the reminder on diving this number by 27 and 37 respectively.
make triplets as written below starting from units place
34.........568..........276
now sum of all triplets = 34+568+276 = 878
divide it by 27 we get reminder as 14
divide it by 37 we get reminder as 27 EXAMPLE. other examples for the clarification of the rule
let the number is 2387850765
triplets are 2...387...850...765
sum of the triplets = 2+387+850+765 = 2004
on revising the steps we get
2......004
sum = 6
divide it by 27 we get reminder as 6
divide it by 37 we get reminder as 6 Is this maths trick helpful? Yes (11394) No (4622) Post / Read comment (47)

TO CALCULATE REMINDER ON DIVIDING THE NUMBER BY 7 11 AND 13 Let me explain this rule by taking examples
consider number 34568276, we have to calculate the reminder on diving this number by 7 11 and 13 respectively.
make triplets as written below starting from units place
34.........568..........276
now alternate sum = 34+276 = 310 and 568
and difference of these sums = 568-310 = 258
divide it by 7 we get reminder as 6
divide it by 11 we get reminder as 5
divide it by 13 we get reminder as 11 EXAMPLE. other examples:-
consider the number 4523895099854
triplet pairs are 4...523...895...099...854
alternate sums are 4+895+854=1753 and 523+099=622
difference = 1131
revise the same tripling process
1......131
so difference = 131-1 = 130
divide it by 7 we get reminder as 4
divide it by 11 we get reminder as 9
divide it by 13 we get reminder as 0