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26th November 2014, 07:53 AM
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Join Date: Apr 2013
Re: IIT-JAM Question Paper

As you want I am here providing you the sample question paper of the IIT-JAM.

Sample Questions :

An X-ray diffraction (XRD) experiment is carried out on a crystalline solid having FCC structure at room temperature. The solid undergoes a phase transformation on cooling to
—20 °C and shows orthorhombic structure with small decrease in its unit cell lengths as compared to the FCC unit cell lengths. As a result, the (311) line of the XRD pattern corresponding to the FCC system
(A) will split into a doublet.
(B) will split into a triplet.
(C) will remain unchanged.
D) will split into two separate doublets.


Light described by the equation E= (90 V/m)[sin(6.28 × 1015 s-1) t + sin(12.56 × 1015 s-1) t] is
incident on a metal surface. The work function of the metal is 2.0 eV. Maximum kinetic energy
of the photoelectrons will be

(A) ) 2.14 eV (B) 4.28 eV (C) 6.28 eV (D) 12.56 eV

A gas of molecular mass m is at temperature T. If the gas obeys Maxwell-Boltzmann velocity
distribution, the average speed of molecules is given by

(A)
m
T kB (B)
m
T kB 2 (C) m
T kB
π
2 (D)
m
T kB
π
8


Consider free expansion of one mole of an ideal gas in an adiabatic container from volume V1
to V2. The entropy change of the gas, calculated by considering a reversible process between
the original state (V1 , T ) to the final state (V2 , T ) where T is the temperature of the system, is
denoted by ΔS1. The corresponding change in the entropy of the surrounding is ΔS2. Which of
the following combinations is correct?
(A) ΔS1 = R ln (V1 / V2 ), ΔS2 = − R ln (V1 / V2 )
(B) ΔS1 = − R ln (V1 / V2 ), ΔS2 = R ln (V1 / V2 )
(C) ΔS1 = R ln (V2 / V1 ), ΔS2 = 0
Q.8
(D) ΔS1 = − R ln (V2 / V1 ), ΔS2 = 0


Equipotential surfaces corresponding to a particular charge distribution are given by
( ) i V z y x = + − + 2 2 2 2 4 , where the values of i V are constants. The electric field E
r
at the
origin is
Q.9
(A) 0 = E
r
(B) x E ˆ 2 =
r
(C) y E ˆ 4 =
r
(D) y E ˆ 4 − =
R

The wave function of a quantum mechanical particle is given by
ψ(x) =
5
3 ϕ1(x) +
5
4 ϕ2(x) ,
where ϕ1(x) and ϕ2(x) are eigenfunctions with corresponding energy eigenvalues − 1 eV and
−2 eV, respectively. The energy of the particle in the state ψ is
(A)
25
41 − eV (B)
5
11 − eV (C)
25
36 − eV (D)
5
7 − eV









Here is the attachment .
Attached Files
File Type: pdf IIT JAM Physics paper.pdf (102.8 KB, 37 views)


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