#1
18th November 2015, 03:36 PM
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CG PET Previous Year Paper
Will you please give here sample question paper for Chhattisgarh Pre Engineering Test (CG PET) examination ?
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#2
19th November 2015, 09:31 AM
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Re: CG PET Previous Year Paper
As you want I am here providing you sample question paper for Chhattisgarh Pre Engineering Test (CG PET) examination. Sample paper : 1. The value of k for which the points (0,0), (2,0), (0,1) and (0,k) lies on a circle is : (1) 1,2 (2) -1,2 (3) 0,2 (4) 0, 1 2. The area of the triangle formed by the tangent and normal at (1, √√ √2) to the circle x2+y2 = y and positive x-axis will be : (1) 1 √3 (2) 4√3 (3) √3 (4) 2√3 3. A straight line makes a triangle of area 5 units with the axis of coordinates and is perpendicular to the line 5x – y = 1, the equation of the line is : (1) x + 5y ± 5 = 0 (2) x – 5y ± 5 √2 = 0 (3) x + 5y ± 5 √2 (4) 5 x + y ± √2 = 0 4. If the points (λλ λ - 2, λλ λ-4), (λλ λ, λλ λ + 1 ) and (λλ λ, λλ λ + 1) and (λλ λ + 4, 16) are collinear then the value of λλ λ will be : (1) – 4 (2) – 5 (3) 4 (4) 5 5. The imaginary part of tan-1 (5i/3) is : (1) log 4 (2) log 2 (3) ∞ (4) 0 6. If x = a + ιι ι, y = ay = bββ β and z = αα α ββ β + br (where ββ β and γγ γ are the imaginary cube roots of unity) then the value of xyz is : (1) 3 ab (2) a3 + b3 (3) a3+b3+3ab (4) a3 – b3 (2) If A is a square matrix their A + AT will be : (1) unit matrix (2) symmetric matrix (3) spew symmetric matrix (4) envertible matrix The sum of the numbers which are divisible by 3 and lies behveen 250 to 1000 is equal to : (1) 156375 (2) 161575 (3) 136577 (4) 135657 (2) If x = a (cos t + tan t/2), y = a sin t, then the value of dy at t = ππ π is : dx 4 (1) a (2) 0 (3) – 1 (4) 1 If the function 2x3 – (x +5 ) is an increasing function then the value x is : (1) 0 < x < 1 (2) – 1 < x < 1 (3) x < - 1 and x > 1 (4) – 1 < x < - 1 The two parts of 20 such that the product of the cube of one and the square of the other is maximum is : (1) 12,8 (2) 8, 12 (3) 16,4 (4) 10,10 The coordinates of the ends of the latus rectum to the parabola x2 = 4ay are : (1) (-2a, a), (2a, a) (2) (a, - 2a), (2a, a) (3) (-a, 2a), (2a, a) (4) (a, 2a), (2a, - a) The area of the square formed by the lines |x| + |y| = 1 is: (1) 1 square unit (2) 8 square unit (3) 2 square unit (4) 4 square unit |
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