#1
14th December 2014, 08:20 AM
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After scoring 66% in 10th, 58% in 12th, and 65% in BCA Am I eligible for TCS
I got 66% in 10th, 58% in 12th, and 65% in BCA, now am I eligible for doing internship in TCS ?
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#2
14th December 2014, 08:46 AM
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Re: After scoring 66% in 10th, 58% in 12th, and 65% in BCA Am I eligible for TCS
Sorry to say you but you are not eligible for doing internship in TCS because you don’t have 60% marks in 12th class. Here I am giving you eligibility criteria for this: Candidate should have 60% and above throughout his / her career. Candidate must not have any backlogs. There should not be a gap of more than 2 years in the education. M.Tech and MCA students having 3 or more than 3 years experience are not allowed. Candidate who are pursuing full time courses are only allowed to attend the recruitment. TCS Selection Procedure: It is based on 3 stages: Written Test Technical Interview Hr interview Here I am giving you some questions of TCS placement paper: 1. Ray writes a two digit number. He sees that the number exceeds 4 times the sum of its digits by 3. If the number is increased by 18, the result is the same as the number formed by reversing the digits. Find the number. a) 35 b) 42 c) 49 d) 57 Solution: Let the two digit number be xy. 4(x + y) +3 = 10x + y .......(1) 10x + y + 18 = 10 y + x ....(2) Solving 1st equation we get 2x - y = 1 .....(3) Solving 2nd equation we get y - x = 2 .....(4) Solving 3 and 4, we get x = 3 and y = 5 2. a, b, c are non negitive integers such that 28a+30b+31c = 365. a + b + c = ? a) Greater than 14 b) less than or equal to 11 c) 13 d) 12 In a calender, Number of months having 28 days = 1 Number of months having 30 days = 4 Number of months having 31 days = 7 28 x 1 + 30 x 4 + 31 x 7 = 365 Here, a = 1, b = 4, c = 7. a+b+c = 12 3. George can do a piece of work in 8 hours. Paul can do the same work in 10 hours, Hari can do the same work in 12 hours. George, paul and hari start the same work at 9 am, while george stops at 11 am, the remaining two complete the work. What time will the work complete? a) 11.30 am b) 12 noon c) 12.30 pm d) 1 pm Let the total work = 120 units. As George completes this entire work in 8 hours, his capacity is 15 units /hour Similarly, the capacity of paul is 12 units / hour the capacity of Hari is 10 units / hour All 3 started at 9 am and worked upto 11 am. So total work done upto 11 am = 2 x (15 + 12 + 10) = 74 Remaining work = 120 - 74 = 46 Now this work is to be done by paul and hari. 46 / (12 + 10) = 2 hours (approx) So work gets completed at 1 pm 4. If x^y denotes x raised to the power y, Find last two digits of (1141^3843) + (1961^4181) a) 02 b) 82 c) 42 d) 22 5 J can dig a well in 16 days. P can dig a well in 24 days. J, P, H dig in 8 days. H alone can dig the well in How many days? a) 32 b) 48 c) 96 d) 24 Assume the total work = 48 units. Capacity fo J = 48 / 16 = 3 units / day Capacity of P = 48 / 24 = 2 units / day Capacity of J, P, H = 48 / 8 = 6 units / day From the above capacity of H = 6 - 2 - 3 = 1 So H takes 48 / 1 days = 48 days to dig the well 6. If a lemon and apple together costs Rs.12, tomato and a lemon cost Rs.4 and an apple costs Rs.8 more than a lemon. What is the cost of lemon? L + A = 12 ...(1) T + L = 4 .....(2) L + 8 = A Taking 1 and 3, we get A = 10 and L = 2 7. 3 mangoes and 4 apples costs Rs.85. 5 apples and 6 peaches costs 122. 6 mangoes and 2 peaches costs Rs.144. What is the combined price of 1 apple, 1 peach, and 1 mango. a) 37 b) 39 c) 35 d) 36 3m + 4a = 85 ..(1) 5a + 6p = 122 ..(2) 6m + 2p = 144 ..(3) (1) x 2 => 6m + 8a = 170 4 x (3) => 6m + 2p = 144 Solving we get 8a - 2p = 56 ..(4) (2) => 5a + 6p = 122 3 x (4) = 24a - 6p = 168 Solving we get a = 10, p = 12, m = 15 So a + p + m = 37 8. An organisation has 3 committees, only 2 persons are members of all 3 committee but every pair of committee has 3 members in common. what is the least possible number of members on any one committee? a) 4 b) 5 c) 6 d) 1 From the (iii) clue, peda must be eaten after jilebi. so Peda should not be eaten on monday. 9. If YWVSQ is 25 - 23 - 21 - 19 - 17, Then MKIGF a) 13 - 11 - 8 - 7 - 6 b) 1 - 2-3-5-7 c) 9 - 8 - 7 - 6 - 5 d) 7 - 8 - 5 - 3 MKIGF = 13 - 11 - 9 - 7 - 6 Note: this is a dummy question. Dont answer these questions 10. Addition of 641 + 852 + 973 = 2456 is incorrect. What is the largest digit that can be changed to make the addition correct? a) 5 b) 6 c) 4 d) 7 |
#3
23rd February 2015, 04:13 PM
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Re: After scoring 66% in 10th, 58% in 12th, and 65% in BCA Am I eligible for TCS
I want to appear in TCS placement test , will you tell me that am I eligible for TCS placement test after scoring 66% in 10th, 58% in 12th, and 65% in BCA?
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#4
23rd February 2015, 04:56 PM
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Re: After scoring 66% in 10th, 58% in 12th, and 65% in BCA Am I eligible for TCS
Hey, you are not eligible for TCS placement exam as for appearing in TCS placement test candidate should have secure minimum 60% marks through out the qualified exams(10th=60%, 12th=60%, graduation =60% / post graduation =60%). Other eligibility criteria: Minimum Age: 18 years and Maximum Age-28 years Experience : Max. 3 years of work experience. Backlog Criteria : No pending backlogs at the time of appearing for the TCS Selection process. TCS Selection Procedure : The selection procedure of TCS consists of following 3 rounds 1. Written Test- (aptitude, reasoning, verbal ability) 2. Technical Interview 3. HR Interview TCS Written Test Pattern: No of questions 35 Time Limit 80 minutes Negative Mark : 1/3 Aptitude/Reasoning/Verbal ability Topics to concentrate Puzzles Probability Time and work Coding and decoding Numbers Simple equations Permutation and combination Average Clocks and calendars Geometry Statement problem Practice more reasoning questions C++, java, OS, DBMS |